Rozwiąż układ równań dla 5x+2y=33-1x i -5x-4y=-33

Rozwiązanie zadanego układu równań metodą podstawiania:

$\begin{cases}5x+2y=33-1x \\ -5x-4y=-33 \end{cases}$

$2y+6x=33-4y-5x=-33 $
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i: Ostateczne rozwiązanie to:

2y = -6x + 33

y = -3x + 33/2
  -5x - 4•(-3x+33/2) = -33
  7x = 33
  7x = 33 

  x = 33/7 
  x = 33/7
  y = -3x+33/2  y = -3(33/7)+33/2 = 33/14 
 {x,y} = {33/7,33/14}