Rozwiąż układ równań dla 2x-5y-2=0 i 3x-6y+1=0

Rozwiązanie zadanego układu równań metodą podstawiania:

$\begin{cases}2x-5y-2=0 \\ 3x-6y+1=0 \end{cases}$

$-5y+2x=2-6y+3x=-1 $
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i: Ostateczne rozwiązanie to:

3x = 6y - 1

x = 2y - 1/3
  2•(2y-1/3) - 5y = 2
  - y = 8/3
  - 3y = 8
  3y = - 8 

  y = - 8/3 
  x = 2y-1/3
  y = -8/3  x = 2(-8/3)-1/3 = -17/3 
 {x,y} = {-17/3,-8/3}