Rozwiąż układ równań dla 1/2x+1/4y=1/4x-1 i -1/4x+1/2y=1/4y+3

Rozwiązanie zadanego układu równań metodą podstawiania:

$\begin{cases}\frac{1}{2x}+\frac{1}{4y}=\frac{1}{4x}-1 \\ -\frac{1}{4x}+\frac{1}{2y}=\frac{1}{4y}+3 \end{cases}$

$ x+y=-4 $
$ -x+y=12 $

i: Ostateczne rozwiązanie to:

y + x = -4 y - x = 12


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y = x + 12

  x + (x +12) = -4
  2x = -16
  2x = - 16 

  x = - 8 
  x = -8
  y = x+12  y = (-8)+12 = 4 
 {x,y} = {-8,4}