Rozwiąż układ równań dla y=1/3x-2 i y+1=0

Rozwiązanie zadanego układu równań metodą podstawiania:

$\begin{cases}y=\frac{1}{3x}-2 \\ y+1=0 \end{cases}$

$ 3y-x=-6 $
$ y=-1 $

i: Ostateczne rozwiązanie to:

x + 3y = -6 y = -1


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  y = - 1 
  3•(-1) - x = -6
  - x = -3
  x = 3 
  y = -1
  x = 3 {y,x} = {-1,3}