Rozwiąż układ równań dla 2x+y=1 i -3+3y=9

Rozwiązanie zadanego układu równań metodą podstawiania:

$\begin{cases}2x+y=1 \\ -3+3y=9 \end{cases}$

$y+2x=13y=12 $
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i: Ostateczne rozwiązanie to:

  3y = 12 

  y = 4 
  2x + (4) = 1
  2x = -3
  2x = - 3 

  x = - 3/2 
  x = -3/2
  y = 4 {x,y} = {-3/2,4}