Rozwiąż układ równań dla x+y/2=3 i 2x-1/3y=5

Rozwiązanie zadanego układu równań metodą podstawiania:

$\begin{cases} x+\frac{y}{2}=3 \\  2x-\frac{y}{3}=5 \end{cases}$

$y+2x=6y+6x=15 $
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i: Ostateczne rozwiązanie to:

y = -2x + 6

  6x - (-2x+6) = 15
  8x = 21
  8x = 21 

  x = 21/8 
  x = 21/8
  y = -2x+6  y = -2(21/8)+6 = 3/4 
 {x,y} = {21/8,3/4}