Rozwiąż układ równań dla 5x-4=3y i 2y+1=3x

Rozwiązanie zadanego układu równań metodą podstawiania:

$\begin{cases}5x-4=3y \\ 2y+1=3x \end{cases}$

$-3y+5x=42y-3x=-1 $
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i: Ostateczne rozwiązanie to:

2y = 3x - 1

y = 3x/2 - 1/2
  5x - 3•(3x/2-1/2) = 4
  x/2 = 5/2
  x = 5
  x = 5 
  x = 5
  y = 3x/2-1/2  y = (3/2)(5)-1/2 = 7 
 {x,y} = {5,7}