Rozwiąż układ równań dla x+3y=2 i 1/10x+1/2y=1

Rozwiązanie zadanego układu równań metodą podstawiania:

$\begin{cases} x+3y=2 \\ \frac{ x}{10}+\frac{y}{2}=1 \end{cases}$

$3y+x=25y+x=10 $
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i: Ostateczne rozwiązanie to:

x = -5y + 10

  (-5y+10) + 3y = 2
  - 2y = -8
  2y = 8 

  y = 4 
  x = -5y+10
  y = 4  x = -5(4)+10 = -10 
 {x,y} = {-10,4}