Matematyka
$f\left(q, r, s, x\right) =$ |
$x{\cdot}\left(\ln\left(x\right)+\ln\left(s\right)+\ln\left(r\right)+\ln\left(q\right)\right)$
Note: Your input has been rewritten/simplified. |
---|---|
$\dfrac{\mathrm{d}\left(f\left(q, r, s, x\right)\right)}{\mathrm{d}x} =$ |
$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(x{\cdot}\left(\ln\left(x\right)+\ln\left(s\right)+\ln\left(r\right)+\ln\left(q\right)\right)\right)}}$ $=\class{steps-node}{\cssId{steps-node-3}{\class{steps-node}{\cssId{steps-node-2}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(x\right)}}{\cdot}\left(\ln\left(x\right)+\ln\left(s\right)+\ln\left(r\right)+\ln\left(q\right)\right)}}+\class{steps-node}{\cssId{steps-node-5}{x{\cdot}\class{steps-node}{\cssId{steps-node-4}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\ln\left(x\right)+\ln\left(s\right)+\ln\left(r\right)+\ln\left(q\right)\right)}}}}$ $=\class{steps-node}{\cssId{steps-node-6}{1}}{\cdot}\left(\ln\left(x\right)+\ln\left(s\right)+\ln\left(r\right)+\ln\left(q\right)\right)+\class{steps-node}{\cssId{steps-node-7}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\ln\left(x\right)\right)}}{\cdot}x$ $=\ln\left(x\right)+\class{steps-node}{\cssId{steps-node-8}{\dfrac{1}{x}}}{\cdot}x+\ln\left(s\right)+\ln\left(r\right)+\ln\left(q\right)$ $=\ln\left(x\right)+\ln\left(s\right)+\ln\left(r\right)+\ln\left(q\right)+1$ |