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Pochodna funkcji 2sin(2)cos(x)

$f\left(x\right) =$	$2{\cdot}\sin\left(2\right){\cdot}\cos\left(x\right)$
$\dfrac{\mathrm{d}\left(f\left(x\right)\right)}{\mathrm{d}x} =$	$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(2{\cdot}\sin\left(2\right){\cdot}\cos\left(x\right)\right)}}$ $=\class{steps-node}{\cssId{steps-node-2}{2{\cdot}\sin\left(2\right){\cdot}\class{steps-node}{\cssId{steps-node-3}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\cos\left(x\right)\right)}}}}$ $=2{\cdot}\sin\left(2\right){\cdot}\class{steps-node}{\cssId{steps-node-4}{\left(-\sin\left(x\right)\right)}}$ $=-2{\cdot}\sin\left(2\right){\cdot}\sin\left(x\right)$

$f\left(x\right) =$

$2{\cdot}\sin\left(2\right){\cdot}\cos\left(x\right)$

$\dfrac{\mathrm{d}\left(f\left(x\right)\right)}{\mathrm{d}x} =$

$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(2{\cdot}\sin\left(2\right){\cdot}\cos\left(x\right)\right)}}$

$=\class{steps-node}{\cssId{steps-node-2}{2{\cdot}\sin\left(2\right){\cdot}\class{steps-node}{\cssId{steps-node-3}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\cos\left(x\right)\right)}}}}$

$=2{\cdot}\sin\left(2\right){\cdot}\class{steps-node}{\cssId{steps-node-4}{\left(-\sin\left(x\right)\right)}}$

$=-2{\cdot}\sin\left(2\right){\cdot}\sin\left(x\right)$