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Pochodna funkcji sqrt(3,x+1)

$f\left(x\right) =$	${\left(x+1\right)}^{\frac{1}{3}}$
$\dfrac{\mathrm{d}\left(f\left(x\right)\right)}{\mathrm{d}x} =$	$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left({\left(x+1\right)}^{\frac{1}{3}}\right)}}$ $=\class{steps-node}{\cssId{steps-node-2}{\dfrac{1}{3}}}{\cdot}\class{steps-node}{\cssId{steps-node-3}{{\left(x+1\right)}^{\frac{1}{3}-1}}}{\cdot}\class{steps-node}{\cssId{steps-node-4}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(x+1\right)}}$ $=\dfrac{\class{steps-node}{\cssId{steps-node-5}{1}}}{3{\cdot}{\left(x+1\right)}^{\frac{2}{3}}}$

$f\left(x\right) =$

${\left(x+1\right)}^{\frac{1}{3}}$

$\dfrac{\mathrm{d}\left(f\left(x\right)\right)}{\mathrm{d}x} =$

$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left({\left(x+1\right)}^{\frac{1}{3}}\right)}}$

$=\class{steps-node}{\cssId{steps-node-2}{\dfrac{1}{3}}}{\cdot}\class{steps-node}{\cssId{steps-node-3}{{\left(x+1\right)}^{\frac{1}{3}-1}}}{\cdot}\class{steps-node}{\cssId{steps-node-4}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(x+1\right)}}$

$=\dfrac{\class{steps-node}{\cssId{steps-node-5}{1}}}{3{\cdot}{\left(x+1\right)}^{\frac{2}{3}}}$