Pochodna funkcji lnx+1

$f\left(x\right) =$	$\ln\left(x\right)+1$
$\dfrac{\mathrm{d}\left(f\left(x\right)\right)}{\mathrm{d}x} =$	$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\ln\left(x\right)+1\right)}}$ $=\class{steps-node}{\cssId{steps-node-2}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\ln\left(x\right)\right)}}$ $=\class{steps-node}{\cssId{steps-node-3}{\dfrac{1}{x}}}$

$f\left(x\right) =$

$\ln\left(x\right)+1$

$\dfrac{\mathrm{d}\left(f\left(x\right)\right)}{\mathrm{d}x} =$

$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\ln\left(x\right)+1\right)}}$

$=\class{steps-node}{\cssId{steps-node-2}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\ln\left(x\right)\right)}}$

$=\class{steps-node}{\cssId{steps-node-3}{\dfrac{1}{x}}}$