Pochodna funkcji sin(5-x)

$f\left(x\right) =$ $-\sin\left(x-5\right)$
Note: Your input has been rewritten/simplified.
$\dfrac{\mathrm{d}\left(f\left(x\right)\right)}{\mathrm{d}x} =$

$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathbf{d}}{\mathbf{d}\boldsymbol{x}}\kern-.25em\left(-\sin\left(x-5\right)\right)}}$

$=\class{steps-node}{\cssId{steps-node-2}{-\class{steps-node}{\cssId{steps-node-3}{\tfrac{\mathbf{d}}{\mathbf{d}\boldsymbol{x}}\kern-.25em\left(\sin\left(x-5\right)\right)}}}}$

$=-\left(\class{steps-node}{\cssId{steps-node-4}{\cos\left(x-5\right)}}{\cdot}\class{steps-node}{\cssId{steps-node-5}{\tfrac{\mathbf{d}}{\mathbf{d}\boldsymbol{x}}\kern-.25em\left(x-5\right)}}\right)$

$=-\class{steps-node}{\cssId{steps-node-6}{1}}{\cdot}\cos\left(x-5\right)$

$=-\cos\left(x-5\right)$

Podziel się rozwiązaniem:

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