Matematyka
$f\left(a, x\right) =$ | $\arcsin\left(\dfrac{a}{x}\right)$ |
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$\dfrac{\mathrm{d}\left(f\left(a, x\right)\right)}{\mathrm{d}x} =$ |
$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\arcsin\left(\dfrac{a}{x}\right)\right)}}$ $=\class{steps-node}{\cssId{steps-node-2}{\dfrac{1}{\sqrt{1-{\left(\dfrac{a}{x}\right)}^{2}}}}}{\cdot}\class{steps-node}{\cssId{steps-node-3}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\dfrac{a}{x}\right)}}$ $=\dfrac{\class{steps-node}{\cssId{steps-node-4}{a{\cdot}\class{steps-node}{\cssId{steps-node-5}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\dfrac{1}{x}\right)}}}}}{\sqrt{1-\dfrac{{a}^{2}}{{x}^{2}}}}$ $=\dfrac{a{\cdot}\dfrac{\class{steps-node}{\cssId{steps-node-8}{-\class{steps-node}{\cssId{steps-node-7}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(x\right)}}}}}{\class{steps-node}{\cssId{steps-node-6}{{x}^{2}}}}}{\sqrt{1-\dfrac{{a}^{2}}{{x}^{2}}}}$ $=\dfrac{-a{\cdot}\class{steps-node}{\cssId{steps-node-9}{1}}}{\sqrt{1-\dfrac{{a}^{2}}{{x}^{2}}}{\cdot}{x}^{2}}$ $=\dfrac{-a}{\sqrt{1-\dfrac{{a}^{2}}{{x}^{2}}}{\cdot}{x}^{2}}$ |