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Pochodna funkcji arctan(3x)

$f\left(x\right) =$	$\arctan\left(3x\right)$
$\dfrac{\mathrm{d}\left(f\left(x\right)\right)}{\mathrm{d}x} =$	$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\arctan\left(3x\right)\right)}}$ $=\class{steps-node}{\cssId{steps-node-2}{\dfrac{1}{{\left(3x\right)}^{2}+1}}}{\cdot}\class{steps-node}{\cssId{steps-node-3}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(3x\right)}}$ $=\dfrac{\class{steps-node}{\cssId{steps-node-4}{3}}}{9{x}^{2}+1}$

$f\left(x\right) =$

$\arctan\left(3x\right)$

$\dfrac{\mathrm{d}\left(f\left(x\right)\right)}{\mathrm{d}x} =$

$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(\arctan\left(3x\right)\right)}}$

$=\class{steps-node}{\cssId{steps-node-2}{\dfrac{1}{{\left(3x\right)}^{2}+1}}}{\cdot}\class{steps-node}{\cssId{steps-node-3}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(3x\right)}}$

$=\dfrac{\class{steps-node}{\cssId{steps-node-4}{3}}}{9{x}^{2}+1}$