Rozwiąż układ równań dla 2x+5y=29 i 2y-3x=4

Rozwiązanie zadanego układu równań metodą podstawiania:

$\begin{cases}2x+5y=29 \\ 2y-3x=4 \end{cases}$

$5y+2x=292y-3x=4 $
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$ctx.strokeStyle="#202020";ctx.strokeText("9",7,48);ctx.moveTo(27,48);ctx.lineTo(291,48);ctx.stroke(); $
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i: Ostateczne rozwiązanie to:

2y = 3x + 4

y = 3x/2 + 2
  2x + 5•(3x/2+2) = 29
  19x/2 = 19
  19x = 38
  19x = 38 

  x = 2 
  x = 2
  y = 3x/2+2  y = (3/2)(2)+2 = 5 
 {x,y} = {2,5}