Pochodna funkcji 1+3cos3x

$f\left(x\right) =$	$3{\cdot}\cos\left(3\right){\cdot}x+1$
	Note: Your input has been rewritten/simplified.
$\dfrac{\mathrm{d}\left(f\left(x\right)\right)}{\mathrm{d}x} =$	$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathbf{d}}{\mathbf{d}\boldsymbol{x}}\kern-.25em\left(3{\cdot}\cos\left(3\right){\cdot}x+1\right)}}$ $=\class{steps-node}{\cssId{steps-node-2}{3{\cdot}\cos\left(3\right)}}$

$f\left(x\right) =$

$3{\cdot}\cos\left(3\right){\cdot}x+1$

Note: Your input has been rewritten/simplified.

$\dfrac{\mathrm{d}\left(f\left(x\right)\right)}{\mathrm{d}x} =$

$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathbf{d}}{\mathbf{d}\boldsymbol{x}}\kern-.25em\left(3{\cdot}\cos\left(3\right){\cdot}x+1\right)}}$

$=\class{steps-node}{\cssId{steps-node-2}{3{\cdot}\cos\left(3\right)}}$