Matematyka
Rozwiązanie zadanego układu równań metodą podstawiania:
\begin{cases}x+1=3
\\ y-x=1
\end{cases}
0?+x=2?-x=1
varc=document.getElementById("myCanvas");
varctx=c.getContext("2d");
ctx.font="18pxArial";
ctx.strokeStyle="#202020";ctx.strokeStyle="#b22222";ctx.strokeText("?",7,24);ctx.font="12pxArial";
ctx.moveTo(27,24);ctx.lineTo(291,24);ctx.stroke();
ctx.strokeStyle="#202020";ctx.strokeText("7",7,48);ctx.moveTo(27,48);ctx.lineTo(291,48);ctx.stroke();
ctx.strokeText("6",7,72);ctx.moveTo(27,72);ctx.lineTo(291,72);ctx.stroke();
ctx.strokeText("5",7,96);ctx.moveTo(27,96);ctx.lineTo(291,96);ctx.stroke();
ctx.strokeText("4",7,120);ctx.moveTo(27,120);ctx.lineTo(291,120);ctx.stroke();
ctx.strokeText("3",7,144);ctx.moveTo(27,144);ctx.lineTo(291,144);ctx.stroke();
ctx.strokeText("2",7,168);ctx.moveTo(27,168);ctx.lineTo(291,168);ctx.stroke();
ctx.strokeText("1",7,192);ctx.moveTo(27,192);ctx.lineTo(291,192);ctx.stroke();
ctx.strokeStyle="#202020";ctx.strokeText("0",7,216);ctx.moveTo(27,216);ctx.lineTo(291,216);ctx.stroke();
ctx.strokeStyle="#202020";ctx.strokeText("-1",7,240);ctx.moveTo(27,240);ctx.lineTo(291,240);ctx.stroke();
ctx.strokeText("-2",7,264);ctx.moveTo(27,264);ctx.lineTo(291,264);ctx.stroke();
ctx.strokeText("-3",7,288);ctx.moveTo(27,288);ctx.lineTo(291,288);ctx.stroke();
ctx.strokeStyle="#202020";ctx.strokeText("-4",19,310);ctx.moveTo(27,0);ctx.lineTo(27,290);ctx.strokeStyle='#eee9e9';ctx.stroke();
ctx.strokeStyle="#202020";ctx.strokeText("-3",43,310);ctx.moveTo(51,0);ctx.lineTo(51,290);ctx.strokeStyle='#eee9e9';ctx.stroke();
ctx.strokeStyle="#202020";ctx.strokeText("-2",67,310);ctx.moveTo(75,0);ctx.lineTo(75,290);ctx.strokeStyle='#eee9e9';ctx.stroke();
ctx.strokeStyle="#202020";ctx.strokeText("-1",91,310);ctx.moveTo(99,0);ctx.lineTo(99,290);ctx.strokeStyle='#eee9e9';ctx.stroke();
ctx.strokeStyle="#202020";ctx.strokeText("0",115,310);ctx.moveTo(123,0);ctx.lineTo(123,290);ctx.strokeStyle='#eee9e9';ctx.stroke();
ctx.strokeStyle="#202020";ctx.strokeText("1",139,310);ctx.moveTo(147,0);ctx.lineTo(147,290);ctx.strokeStyle='#eee9e9';ctx.stroke();
ctx.strokeStyle="#202020";ctx.strokeText("2",163,310);ctx.moveTo(171,0);ctx.lineTo(171,290);ctx.strokeStyle='#eee9e9';ctx.stroke();
ctx.strokeStyle="#202020";ctx.strokeText("3",187,310);ctx.moveTo(195,0);ctx.lineTo(195,290);ctx.strokeStyle='#eee9e9';ctx.stroke();
ctx.strokeStyle="#202020";ctx.strokeText("4",211,310);ctx.moveTo(219,0);ctx.lineTo(219,290);ctx.strokeStyle='#eee9e9';ctx.stroke();
ctx.strokeStyle="#202020";ctx.strokeText("5",235,310);ctx.moveTo(243,0);ctx.lineTo(243,290);ctx.strokeStyle='#eee9e9';ctx.stroke();
ctx.strokeStyle="#202020";ctx.strokeStyle="#b22222";ctx.font="18pxArial";
ctx.strokeText("x",259,310);ctx.font="11pxArial";
ctx.moveTo(267,0);ctx.lineTo(267,290);ctx.strokeStyle='#eee9e9';ctx.stroke();
ctx.beginPath();ctx.moveTo(169,0);ctx.lineTo(169,288);ctx.lineWidth=3;ctx.strokeStyle="#ff3399";ctx.stroke();
ctx.beginPath();ctx.moveTo(289,24);ctx.lineTo(27,288);ctx.lineWidth=3;ctx.strokeStyle="#006633";ctx.stroke();
i: Ostateczne rozwiązanie to:
x = 2
-(2) + y = 1
y = 3
y = 3
x = 2
y = 3 {x,y} = {2,3}